Monday, August 23, 2010

Experiment 1:

Calculating and measuring resistors:

Value (Calculating colour codes)

Measuring(Multimeter)

Brown- Black- Red- Gold

1 - 0 - * - 100 - ±5% = 1000W(1kW)

997W

Brown- Black- Brown- Gold

1 - 0 - * - 10 - ±5% = 100W

098.1W

Browngreen Orange - Gold

1 - 5 - * - 1000 - ±5% = 10000W(10k)

9.98kW

Brown – Black – Yellow - Gold

1- 0 - * - 10000 - ±5% = 100000W(100k)

99.5kW

OrangeWhiteBrown - Gold

3 - 9 - * - 10 - ±5% = 390W

380.5W

YellowViolet – Black – Black - Brown

4 - 7 - 0 - * - 1 ±1% = 470W

467W

Choice of two resistors and their individual resistance values measured with a multimeter:

Resistor 1: 380.5 Ω Resistor 2: 98.1 Ω

Put these two resistors together in Series (end to end, one right after another) calculate and then measure their combined value

Calculated value 1 and 2 in series: 378.6 Ω

Measured value 1 and 2 in series: 482 Ω

Put these two resistors together in Parallel (connect both ends when they are side-by-side). Calculate and then measure their combined value. Show working:

Calculated value 1 and 2 in Parallel: 79.59 Ω

Measured value 1 and 2 in Parallel: 78.7 Ω

What principal of electricity have you demonstrated with this? Explain:

This principal is the Ohm’s Law:

Series: Two resistors connected in series, their combined resistance is equal to each resistance added together.

Parallel: Two resistors connected in parallel, their combined resistance is less than the smallest resistor.

No comments:

Post a Comment